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A 32 B 48 C 64 D 96
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2White balls 3 Black balls 4 Red balls Three balls aredrawn Total possiblecombination ⇒9P3 Combination withoutblack ⇒2C2×4C1+2C1×4C2+4C3 The combination withatleast one black ⇒9×8×73×2×1−[1×4+2×122+4]⇒12(7)−[20]⇒84−20=64 64 Combinationinclude atleast one black Hence the correctanswer is 64
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